b-5/3-2b^2+4b/3b=b+2/3

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Solution for b-5/3-2b^2+4b/3b=b+2/3 equation: 



b-5/3-2b^2+4b/3b=b+2/3

We move all terms to the left:

b-5/3-2b^2+4b/3b-(b+2/3)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

-2b^2+b+4b/3b-(+b+2/3)-5/3=0

We get rid of parentheses

-2b^2+b+4b/3b-b-2/3-5/3=0

We calculate fractions


-2b^2+b-b=0

We add all the numbers together, and all the variables

-2b^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-4}=0$

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